bzoj1000: A+B Problem

Description

输入两个数字, 输出它们之和

Input

一行两个数字 A, B (0<=A, B<100)

Output

输出这两个数字之和

Sample Input

1 2

Sample Output

3

HINT

Q: Where are the input and the output? A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use ‘scanf’ in C or ‘cin’ in C++to read from stdin, and use ‘printf’ in C or ‘cout’ in C++to write to stdout. You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a “Wrong Answer”. User programs are not allowed to open and read from/write to files. You will get a “Runtime Error” or a “Wrong Answer” if you try to do so. Here is a sample solution for problem 1000 using C++/G++:

#include <iostream>
using namespace std;
int  main()
{
    int a,b;
    cin >> a >> b;
    cout << a+b << endl;
    return 0;
    }

It ‘s important that the return type of main () must be int when you use G++/GCC, or you may get compile error. Here is a sample solution for problem 1000 using C/GCC:

#include <stdio.h>

int main()
{
    int a,b;
    scanf(&quot;%d %d&quot;,&amp;a, &amp;b);
    printf(&quot;%d\n&quot;,a+b);
    return 0;
}

Here is a sample solution for problem 1000 using PASCAL:

program p1000(Input,Output);
var
  a,b:Integer;
begin
   Readln(a,b);
   Writeln(a+b);
end.

Here is a sample solution for problem 1000 using JAVA: Now java compiler is jdk 1. 5, next is program for 1000

import java.io.*;
import java.util.*;
public class Main
{
    public static void main(String args[]) throws Exception
    {
        Scanner cin=new Scanner(System.in);
        int a=cin.nextInt(),b=cin.nextInt();
        System.out.println(a+b);
    }
}

Old program for jdk 1. 4

import java.io.*;
import java.util.*;

public class Main
{
    public static void main (String args[]) throws Exception
    {
        BufferedReader stdin =
            new BufferedReader(
                new InputStreamReader(System.in));

        String line = stdin.readLine();
        StringTokenizer st = new StringTokenizer(line);
        int a = Integer.parseInt(st.nextToken());
        int b = Integer.parseInt(st.nextToken());
        System.out.println(a+b);
    }
}

Source

一道水的不能再水的题, 只是为了放上来测试一下oi-cliassistant.

#include <iostream>
using namespace std;

int main(int argc, char** argv)
{
    int a, b;
    cin >> a >> b;
    cout << a + b << endl;
    return 0;
}

import random
print('%d %d\n' % (random.choice(range(1, 1073741823)), random.choice(range(1, 1073741823))))